Search

Thursday 23 June 2016

Mastering Physics: Exercise 22.10

Mastering Physics: Exercise 22.10


A point charge q1 = 3.80 nC is located on the x-axis at x = 2.10 m , and a second point charge q2 = -6.20 nC is on the y-axis at y = 1.15 m .


Part A

Question: What is the total electric flux due to these two point charges through a spherical surface centered at the origin and with radius r1 = 0.555 m ?

Answer:  Φ =  0  N⋅m^2/C 


Part B

Question: What is the total electric flux due to these two point charges through a spherical surface centered at the origin and with radius r2 = 1.55 m ?

Answer: 
Φ =  q_enclosed/ (ϵ_0)
Φ = −6.2×10^(−9) / 8.85 ×10^(−12)
Φ =  -701  N⋅m^2/C


Part C

Question: What is the total electric flux due to these two point charges through a spherical surface centered at the origin and with radius r3 = 2.70 m ?

Answer: 
Φ =  q1/ (ϵ_0) + q2/ (ϵ_0)
Φ = 3.8×10^(−9) / 8.85 ×10^(−12)   +   -701  N⋅m^2/C
Φ =  -271  N⋅m^2/C  

No comments:

Post a Comment